State and prove the Theorem on the Angle Sum Property of a Triangle.
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Answer:
- Construction: Draw a line PQ parallel to side BC of the given triangle and passing through point A. Thus, the sum of the interior angles of a triangle is 180°. Theorem: If any one side of a triangle is produced then the exterior angle so formed is equal to the sum of two interior opposite angles.
Step-by-step explanation:
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Step-by-step explanation:
Theorem 1: Angle sum property of triangle states that the sum of interior angles of a triangle is 180°.
Proof:
Consider a ∆ABC, as shown in the figure below. To prove the above property of triangles, draw a line PQ←→ parallel to the side BC of the given triangle.
Angle sum property of a triangle theorem 1
Since PQ is a straight line, it can be concluded that:
∠PAB + ∠BAC + ∠QAC = 180° ………(1)
Since PQ||BC and AB, AC are transversals,
Therefore, ∠QAC = ∠ACB (a pair of alternate angle)
Also, ∠PAB = ∠CBA (a pair of alternate angle)
Substituting the value of ∠QAC and∠PAB in equation (1),
∠ACB + ∠BAC + ∠CBA= 180°
Thus, the sum of the interior angles of a triangle is 180°.
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