Question

State and write mathematical expression
for Dalton's law of partial pressure and explain it with suitable example​

Answer 1

✨HERR IS YOUR ANSWER

ACCORDING TO DALTON'S LAW OF PARTIAL PRESSURE..

the total pressure of a container with constant volume is the summation of PARTIAL PRESSURE .

OF DIFFERENT COMPONENTS/GASES PRESENT IN THAT CONTAINER .

PTOTAL = Pa + Pb +Pc

where :- Pa is partial pressure of component a .

Pb is partial pressure of component b.

Pb is partial pressure of component b.Pc is partial pressure of component c.

if a,b,c are the different component present in a container of CONSTANT pressure.

&

partial PRESSURE of component A :-

= mole fraction × total PRESSURE.

hope it helps you ☺

Answer 2

Explanation:

Dalton's Law of Partial Pressure:-

i)  Statement:-

The partial pressure of a mixture of two or more non - reactive gases is the sum of the partial pressures of the individual gases in the mixture.

ii) Explanation:-

Dalton's law can be mathematically expressed as:

P total = P1 + P2 + P3 ---- 1

Applying ideal gas equation to individual components.

P1V = n1RT ---- 2

P2V = n2RT ---- 3

P3V = n3RT ---- 4

Using equation 2,3 and 4 in equation 1, we get

P total = n1RT / V + n2RT / V + n3RT / V ---- 5

Therefore, taking the ratio of equation 2 and 5 we get,

Rate of effusion :- r =PA / √2πRTM

Comparison of times taken for the same volume of two gases to diffuse.

r1 / r2 = √M2 / M1

V1 / T1 /V2 / T2 = √M2 / M1

V1 * T1 / V2 * T2 = √M2 / M1

If  V1 = V2, then

t2 / t1 = √M2 / M1

Comparison of the volume of two gases that diffuses in same time

r1 / r2 = √M1 / M2

V1 / T1 /V2 / T2 = √M2 / M1

If t1 = t2, then

V1 / V2 = √M2 / M1

Hope it helps you....