state any six characterstics /properties of scaler product or dot produtc
Answers
Answer:
Properties Of Scaler Product
Property 1. The scaler product of a vector and itself is a positive real number.
Property 2. The scalar product is commutative.
Property 3. The scalar product is pseudo associative.
Property 4. The scalar product distributive with regard to the sum of vectors.
Properties Of Dot Product
Property 1: Dot product of two vectors is commutative i.e. a.b = b.a = ab cos θ.
Property 1: Dot product of two vectors is commutative i.e. a.b = b.a = ab cos θ.Property 2: If a.b = 0 then it can be clearly seen that either b or a is zero or cos θ = 0 ⇒θ = π2. It suggests that either of the vectors is zero or they are perpendicular to each other.
Property 1: Dot product of two vectors is commutative i.e. a.b = b.a = ab cos θ.Property 2: If a.b = 0 then it can be clearly seen that either b or a is zero or cos θ = 0 ⇒θ = π2. It suggests that either of the vectors is zero or they are perpendicular to each other.Property 3: Also we know that using scalar product of vectors (pa).(qb)=(pb).(qa)=pq a.b
Property 1: Dot product of two vectors is commutative i.e. a.b = b.a = ab cos θ.Property 2: If a.b = 0 then it can be clearly seen that either b or a is zero or cos θ = 0 ⇒θ = π2. It suggests that either of the vectors is zero or they are perpendicular to each other.Property 3: Also we know that using scalar product of vectors (pa).(qb)=(pb).(qa)=pq a.bProperty 4: The dot product of a vector to itself is the magnitude squared of the vector i.e. a.a = a.a cos 0 = a2
Property 1: Dot product of two vectors is commutative i.e. a.b = b.a = ab cos θ.Property 2: If a.b = 0 then it can be clearly seen that either b or a is zero or cos θ = 0 ⇒θ = π2. It suggests that either of the vectors is zero or they are perpendicular to each other.Property 3: Also we know that using scalar product of vectors (pa).(qb)=(pb).(qa)=pq a.bProperty 4: The dot product of a vector to itself is the magnitude squared of the vector i.e. a.a = a.a cos 0 = a2Property 5: The dot product follows the distributive law also i.e. a.(b + c) = a.b + a.c
Property 1: Dot product of two vectors is commutative i.e. a.b = b.a = ab cos θ.Property 2: If a.b = 0 then it can be clearly seen that either b or a is zero or cos θ = 0 ⇒θ = π2. It suggests that either of the vectors is zero or they are perpendicular to each other.Property 3: Also we know that using scalar product of vectors (pa).(qb)=(pb).(qa)=pq a.bProperty 4: The dot product of a vector to itself is the magnitude squared of the vector i.e. a.a = a.a cos 0 = a2Property 5: The dot product follows the distributive law also i.e. a.(b + c) = a.b + a.cProperty 6: In terms of orthogonal co-ordinates for mutually perpendicular vectors it is seen that i^.i^ = j^.j^= k^.k^ =1
Explanation:
I hope you have got your answer..
But I don't know the last two properties of scalar product.