State any two factors on which the resistance of a cylindrical depends. Compare the resistance of a conductor of length 'L' and area of cross section 'A' with that of another conductor of same material but of length and area of across section half and double respectively of the former.
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Resistance of a conductor directly depends upon Length of the wire L
Inversely depends upon Area of Cross section of the conductor 1/A
Nature of material used.
Therefore, R=ρ L/A
Length of the conductor is double, means you are stretching that given length to double it. As a result, the wire becomes thin due to stretching. So its area of cross section will be halved(Since the volume remains constant). So new resistance RN = ρ 2L/A/2 = 4. ρ.L/A =4R
Hence the new resistance will become 4 times.
hope it might help you
Inversely depends upon Area of Cross section of the conductor 1/A
Nature of material used.
Therefore, R=ρ L/A
Length of the conductor is double, means you are stretching that given length to double it. As a result, the wire becomes thin due to stretching. So its area of cross section will be halved(Since the volume remains constant). So new resistance RN = ρ 2L/A/2 = 4. ρ.L/A =4R
Hence the new resistance will become 4 times.
hope it might help you
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