Physics, asked by shh2220204sri, 14 hours ago

state biot - savart law . obtain as expression for the magnetic field at the center of a coil bent in the form of a square of side 2a carrying current I ?​

Answers

Answered by sankarbarick06
0

Answer:

The Biot-Savart Law is an equation that describes the magnetic field created by a current-carrying wire, and allows you to calculate its strength at various points.

Here,

I= current in the loop

R= radius of the loop

X= distance between O and P

dl= conducting element of the loop

According to the Biot-Savart law,

Magnetic Field at a point P is,

dB space equals space fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction space fraction numerator straight I space vertical line dl space straight x space straight r vertical line over denominator straight r cubed end fraction

straight r squared space equals space space straight x squared space plus space straight R squared

Since space dl space and space straight r space is space perpendicular comma space

vertical line dl space straight x space straight r vertical line space equals space straight r space dl

Therefore comma

dB space equals space fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction. space fraction numerator straight I. space dl over denominator left parenthesis straight x squared plus straight R squared right parenthesis end fraction

Again,

dB has two components: dB_x and dB_y

dB_y is cancelled out and the x-component remains.

Therefore

dB subscript straight x space equals space dB space cos space straight theta

cos space straight theta space equals space fraction numerator straight R over denominator left parenthesis straight x squared plus straight R squared right parenthesis to the power of bevelled 1 half end exponent end fraction

therefore space dB subscript straight x space equals space fraction numerator straight mu subscript straight o straight I space dl over denominator 4 straight pi end fraction. space fraction numerator straight R over denominator left parenthesis straight x squared space plus space straight R squared right parenthesis to the power of bevelled 3 over 2 end exponent end fraction

Thus, summation of dl over the loop is given by:

straight B subscript straight x straight i with hat on top space equals space fraction numerator straight mu subscript straight o space straight I space straight R squared over denominator 2 space left parenthesis straight x squared plus straight R squared right parenthesis to the power of bevelled 3 over 2 end exponent end fraction space straight i with hat on top

For Nturns, B=

2(x

2

+R

2

)

3/2

μ

o

NIR

2

Magnetic field lines due to a circular current carrying coil is,

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