Question

state BPT theorm and prove it also

Answer 1

Theorem 6.2 - Converse of Basic Proportionality Theorem→. ... Theorem 6.1: If a line is drawn parallel to one side of a triangle to intersect the other two side in distinct points, the other two sides are divided in the same ratio. Given: Δ ABC where DE ∥ BC To Prove ...

Answer 2

Answer:

Step-by-step explanation

To prove - AD/DB=AE/EC

*let us join BE and CD and then draw DM perpendicular to AC and EN perpendicular to AB.

NOW,area of triangle ADE = (1/2 Base * Height) = 1/2 AD * EN

so, ar(ADE)=1/2 AD*EN

similarly, ar(BDE)=1/2 DB*EN

ar(ADE)=1/2 AE*DM. and

ar(DEC)=1/2 EC*DM

Therefore, ar(ADE)/ar(BDE)= AD/DB

and. ar(ADE)/ar(DEC)= AE/EC

so, ar(BDE) = ar(DEC)

Therefore, AD/DB = AE/EC