State buckingham's pi- theorem. Why the theorem is considered superior even the rayleigh's method for dimensional analysis?
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So, why Buckingham's pi-theorem is considered superior even the Rayleigh's method for dimensional analysis?
Well, if we have more variables than the number of fundamental dimensions then rayleigh's theorem is more laborious.
Dimensional analysis can be done for n variables with Buckingham's pi-theorem, but it is much more difficult to use.
Thus, we can consider that Buckingham's pi-theorem is superior than rayleigh's method for dimensional analysis.
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State Buckingham’s π- theorem. Describe Rayleigh’s method for dimensional analysis. How are repeating variable selected for dimension analysis
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