Question

State, by writing first four
expansion of the following, whe
(1) (a-b)-3 (ii) (a+b)-4
(iii) (a+b)1/4 (iv) (a−b)-1/4
(v) (a+b)-1/3
Simplify first three terms in the​

Answer 1

Step-by-step explanation:

(1) (a-b)-3 = -3a+3b

(ii) (a+b)-4 = -4a -4b

(iii) (a+b)1/4 = a/4 + b/4

(iv) (a−b)-1/4 = -a/4 + b/4

(v) (a+b)-1/3 = -a/3 - b/3

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Answer 2

Answer:

1. 3b-3a=3(b-a);

2.-(4a+4b)= -4a-4b

3.1/4a+1/4b

4. 1/4b-1/4a

5. -1/3a-1/3b