Physics, asked by Anonymous, 7 months ago

state coloumb's law...............

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Answered by rakzhana01

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According to Coulomb’s law, the force of attraction or repulsion between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. It acts along the line joining the two charges considered to be point charges.

$Coulomb’s Law Formula: F ∝ q1q2/d2$

where,

ε is absolute permittivity,

K or εr is the relative permittivity or specific inductive capacity
ε0 is the permittivity of free space.
K or εr is also called a dielectric constant of the medium in which the two charges are placed.

$F12=4π∈01−r122q1q2r^12;F12=−F21$

Here F12 is the force exerted by q1 on q2 and F21 is the force exerted by q2 on q1.

Coulomb’s law holds for stationary charges only which are point sized. This law obeys Newton’s third law

$(ieF12=−F21)$

Force on a charged particle due to a number of point charges is the resultant of forces due to individual point charges i.e.

$F=F1+F2+F3+……$

If the force between two charges in two different media is the same for different separations, F=

$14π∈01r2q1q2 = constant .$

$Kr2 = constant or K1r12 = K2r22$

If the force between two charges separated by a distance ‘r0’ in a vacuum is same as the force between the same charges separated by a distance ‘r’ in a medium, then from Coulomb’s Law; Kr^2 = r0^2

Answered by atharva405850

Answer:

$]<body bgcolor="black"><marquee>$ Coulomb's law, or Coulomb's inverse-square law, is an experimental law of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force.

Formula

F = k \frac{q_1q_2}{r^2}

F = electric force

k = Coulomb constant

q_1, q_2 = charges

r = distance of separation

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