Question

State explain and derive the expression for law of conservation of momentum

Answer 1

Answer:

Explanation:

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Conservation 0f Momentum➫ A system in which the momentum of a system is constant if there are no external forces acting on the system.

Prove: Conservation 0f Momentum:-▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃▃⤵

➧Let the Body A = m1 & B = m2

➧Let their velocity be u1 & u2

(u1 > u2)

➧Momentum of Body

A = m1u1 & B = m2u2

❱ Initial & Final momentum of System

➾ m1u1 + m2u2

◉ Body A exert force of Action

➾ Fᴀʙ on Body B.

◉ Body B exert force of Reaction

➾ Fʙᴀ on Body A.

▸ Fᴀʙ = Body A

➾ m1 (v1 - u1) / t

▸ Fʙᴀ = Body B

➾ m2 (v2 - u2) / t

▸ Since, Action = - reaction

▸ So, Fᴀʙ = - Fʙᴀ

m1 (v1 - u1) / t = - m2 (v2 - u2) / t

▸ m1v1 - m1u1 = m2v2 + m2u2

▸ m1v1 - m2v2 = m1u1 + m2u2...✔

_________

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Answer 2

Answer:

Newton's third law states that for a force applied by an object A on object B, object B exerts back an equal force in magnitude, but opposite in direction. This idea was used by Newton to derive the law of conservation of momentum. ... B=m_{2}(v_{2}-u_{2}) (change in momentum of particle B)