Question

State flund rule??write electronic configuration of ferrous

Answer 1

electronic configuration of Fe

1s²,2s²,2p6,3s²,3p6,3d6,4s²

Answer 2

Answer : The electronic configuration of Ferrous will be, $1s^22s^22p^63s^23p^63d^6$

Explanation :

Hund's rule : According to the hund's rule, the electrons are singly filled first in each orbital having same spin, then only pairing occurs.

As we know that the iron with the valance of two is called as ferrous. That means iron is in (+2) oxidation state. Two electrons will be removed from the electronic configuration of Fe.

The electronic configuration of Fe is, $1s^22s^22p^63s^23p^64s^23d^6$

And, the electronic configuration of Ferrous will be, $1s^22s^22p^63s^23p^63d^6$