State fundamental theorem of arithmetic. Is 7×11×13+13, a composite number ? Justify.
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→Fundamental Theorem of Arithmetic =" every composite number can be expressed or factorise as a product of primes, and this factorising is unique apart from the order in which the prime factors occur."
★it simply says that every composite number can be factorised as a product of primes.
★composite number= number having more than two factors i.e. other than 1 and itself are called composite numbers
= 7 x 11 x 13 + 13
(taking 13 as common)
= 13(7 x 11 x 1+1)
= 13( 77+1)
= 13( 78)
we can see that the given expression has more than two factors, hence it is a composite number
_______________
★it simply says that every composite number can be factorised as a product of primes.
★composite number= number having more than two factors i.e. other than 1 and itself are called composite numbers
= 7 x 11 x 13 + 13
(taking 13 as common)
= 13(7 x 11 x 1+1)
= 13( 77+1)
= 13( 78)
we can see that the given expression has more than two factors, hence it is a composite number
_______________
Answered by
2
Answer:
Fundamental Theorem of Arithmetic =" every composite number can be expressed or factorise as a product of primes, and this factorising is unique apart from the order in which the prime factors occur."
★it simply says that every composite number can be factorised as a product of primes.
★composite number= number having more than two factors i.e. other than 1 and itself are called composite numbers
= 7 x 11 x 13 + 13
(taking 13 as common)
= 13(7 x 11 x 1+1)
= 13( 77+1)
= 13( 78)
we can see that the given expression has more than two factors, hence it is a composite number
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