state gauss law of a E = 2kd/r with solution..???
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Step-by-step explanation:
The electric field near the plane charge sheet is E = σ/2ε0 in the direction away from the sheet. At the given area, the field is along the Z-axis.
The area = πr2 = 3.14 × 1 cm2 = 3.14 × 10-4 m2.
The angle between the normal to the area and the field is 600.
Hence, according to Gauss theorem, the flux = = E.ΔS cos θ = σ/2ε0 × pr2 cos 60º
== 17.5 N-m2C-1.
hope it's helps....
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