Question

State Gauss’s law in electrostatics. A thin conducting solid sphere of radius R has charge Q spread

uniformly over its surface. Using Gauss theorem, derive an expression for the electric field

{a} at a point outside the solid sphere.

{b} at a point on the solid sphere.

{c} at a point inside the solid sphere.​

Answer 1

Answer:

option (a)

Explanation:

Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum.

In the diagram, O is the centre of the spherical shell of radius R, and charge enclosed by the spherical shell is q

.Let a point A is outside the spherical shell, where we have to calculate the electric field.The distance between the centre of spherical shell and the point A.