State Gauss’s law in electrostatics. A thin conducting solid sphere of radius R has charge Q spread
uniformly over its surface. Using Gauss theorem, derive an expression for the electric field
{a} at a point outside the solid sphere.
{b} at a point on the solid sphere.
{c} at a point inside the solid sphere.
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Answer:
option (a)
Explanation:
Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum.
In the diagram, O is the centre of the spherical shell of radius R, and charge enclosed by the spherical shell is q
.Let a point A is outside the spherical shell, where we have to calculate the electric field.The distance between the centre of spherical shell and the point A.
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