Question

State gauss's theorem in electrostatics .using theorem derive an expression for the electric field intensity at any point outside a spherical cell

Answer 1

Answer:

According to Gauss’s theorem the net-outward normal electric flux through any closed surface of any shape is equivalent to 1/ε0 times the total amount of charge contained within that surface.

Explanation:

Let the charge be = q

Let us construct the Gaussian sphere of radius = r

Now, Consider , A surface or area ds having having ds (vector)

Normal having the flux at ds:

Flux at ds:

d e = E (vector) d s (vector) cos θ

But , θ = 0

Therefore, Total flux:

C = f d Φ

E 4 π r2

Therefore,

σ = 1 / 4πɛo q / r2 × 4π r2

σ = q / ɛo