Science, asked by yadaushasree, 5 months ago

state guass's law in electrostatics and applying guass's law derive an expression for electric intensity due to an infinite long straight charged wire

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Answered by Yashu2012
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Answer:

Solution : Gauss. law in electrostatics states that the total electric flux overa closed surface in free space is `(1)/(in_(0))` times the net charge enclosed within that surface. Mathematically, for a closed surface <br> `phi_(E)=ointvecE. hatn ds = (1)/(in_(0))(Q)` where Q = total charge enclosed.

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