Physics, asked by nikhilvikash2002, 1 year ago

State Kirchhoff's law for electrical circuit and obtain balancing condition in case of wheatstone's network.​

Answers

Answered by jillpatelj7
8

Explanation:

Kirchhoff's laws are fundamental to circuit theory. They quantify how current flows through a circuit and how voltage varies around a loop in a circuit.

Kirchhoff's current law (1st Law) states that current flowing into a node (or a junction) must be equal to current flowing out of it. This is a consequence of charge conservation.

Kirchhoff's voltage law (2nd Law) states that the sum of all voltages around any closed loop in a circuit must equal zero. This is a consequence of charge conservation and also conservation of energy.

Answered by ashishkumaranuj108
1

Answer:

History About Gustav Robert Kirchhoff

Gustav Robert Kirchhoff, a German physicist, was born on March 12, 1824, in Konigsberg, Prussia. His first research topic was on the conduction of electricity. This research led to Kirchhoff formulating the Laws of Closed Electric Circuits in 1845. These laws were eventually named after Kirchhoff and are now known as Kirchhoff’s Voltage and Current Laws.

What are Kirchhoff’s Laws?

In 1845, a German physicist, Gustav Kirchhoff developed a pair of laws that deal with the conservation of current and energy within electrical circuits. These two laws are commonly known as Kirchhoff’s Voltage and Current Law. These laws help in calculating the electrical resistance of a complex network or impedance in case of AC and the current flow in different streams of the network. In the next section, let us look at what these laws state.

Kirchhoff’s First Law or Kirchhoff’s Current Law-

The total current entering a junction or a node is equal to the charge leaving the node as no charge is lost.

Kirchhoff’s Second Law or Kirchhoff’s Voltage Law-

-The voltage around a loop equals to the sum of every voltage drop in the same loop for any closed network and also equals to zero.

Kirchhoff’s Law Solved Example

If R1 = 2Ω, R2 = 4Ω, R3 = 6Ω, determine the electric current that flows in the circuit below.

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