Question

state nature of roots of equation M^ 2 + 16M + 64 = 0​

Answer 1

Answer:

Step-by-step explanation:

The first term is,  m2  its coefficient is  1 .

The middle term is,  -16m  its coefficient is  -16 .

The last term, "the constant", is  -36  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -36 = -36  

Step-2 : Find two factors of  -36  whose sum equals the coefficient of the middle term, which is   -16 .

     -36    +    1    =    -35  

     -18    +    2    =    -16    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -18  and  2  

                    m2 - 18m + 2m - 36

Step-4 : Add up the first 2 terms, pulling out like factors :

                   m • (m-18)

             Add up the last 2 terms, pulling out common factors :

                   2 • (m-18)

Step-5 : Add up the four terms of step 4 :

                   (m+2)  •  (m-18)

            Which is the desired factorization