state nature of roots of equation M^ 2 + 16M + 64 = 0
Answers
Answer:
Step-by-step explanation:
The first term is, m2 its coefficient is 1 .
The middle term is, -16m its coefficient is -16 .
The last term, "the constant", is -36
Step-1 : Multiply the coefficient of the first term by the constant 1 • -36 = -36
Step-2 : Find two factors of -36 whose sum equals the coefficient of the middle term, which is -16 .
-36 + 1 = -35
-18 + 2 = -16 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -18 and 2
m2 - 18m + 2m - 36
Step-4 : Add up the first 2 terms, pulling out like factors :
m • (m-18)
Add up the last 2 terms, pulling out common factors :
2 • (m-18)
Step-5 : Add up the four terms of step 4 :
(m+2) • (m-18)
Which is the desired factorization