Question

state newton's 2nd law of motion and also write it's mathematical formulation​

Answer 1

Answer:

Newton's Second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system. 

Force applied is directly proportional to the product of mass and acceleration .

Let  be the initial and final momentums respectively.

According to newton's second law :- 

pf - pi / t ∝ F 

We know that, Momentum ( P) = mv .

Let v be the final and u be the initial velocity .

Now, 

mv - mu / t ∝ F 

F ∝ m ( v-u) /t

F ∝ ma. 

F = kma. 

Here, K is the proportionality constant. It's value is 1 .

Units of Force are given by the units of mass and acceleration. Units of force is Kgm/s² .

In accordance to honour the contributions of Newton, 1 kgm/s² is termed as 1 Newton.

Explanation:

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Answer 2

Answer:

Newton's second law states that

'the force acting on a body is directly proportional to the rate of change of momentum of the body and the change in the momentum takes place in the direction of the force'

This law help us to measure the amount of force. So,it is called as 'law of force'. Let 'm' be the mass of a moving body,moving along a straight line with an initial speed 'u' . After a time interval of 't' , the velocity of the body changes to 'v' due to the impact of an unbalanced force F.

Initial momentum of the body Pi= mu

Final momentum of the body Pf= mv

Change in momentum ∆P = Pf - Pi

= mv - my

By Newton's second law of motion,

Force , F inversely proportional to the rate of change of momentum

$f \alpha \frac{change \: in \: momentum}{time}$

$f = \frac{mv - mu}{t}$

$f = \frac{km(v - u)}{t}$

Here k is the proportional constant k=1 in all system of units. hence,

$f = \frac{m(v - u)}{t}$

since acceleration = change in velocity / time

hence, a = (v-u) /t hence we have

F= ma

Force =mass x acceleration