State Newton’s second law of motion. Derive a mathematical expression for Newton’s second law.
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Newton's Second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system.
Force applied is directly proportional to the product of mass and acceleration .
Let be the initial and final momentums respectively.
According to newton's second law :-
pf - pi / t ∝ F
We know that, Momentum ( P) = mv .
Let v be the final and u be the initial velocity .
Now,
mv - mu / t ∝ F
F ∝ m ( v-u) /t
F ∝ ma.
F = kma.
Here, K is the proportionality constant. It's value is 1 .
Units of Force are given by the units of mass and acceleration. Units of force is Kgm/s² .
In accordance to honour the contributions of Newton, 1 kgm/s² is termed as 1 Newton.
Force applied is directly proportional to the product of mass and acceleration .
Let be the initial and final momentums respectively.
According to newton's second law :-
pf - pi / t ∝ F
We know that, Momentum ( P) = mv .
Let v be the final and u be the initial velocity .
Now,
mv - mu / t ∝ F
F ∝ m ( v-u) /t
F ∝ ma.
F = kma.
Here, K is the proportionality constant. It's value is 1 .
Units of Force are given by the units of mass and acceleration. Units of force is Kgm/s² .
In accordance to honour the contributions of Newton, 1 kgm/s² is termed as 1 Newton.
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