State Newton's second law of motion use this to find the method to measure force acting on the object
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Newton's Second law of motion :- The rate of change of momentum is directly proportional to the force applied on the system.
m= mass of the body
u= initial velocity of the body
v= final velocity of the body
t= time for which the force is applied
F = an external force applied on body
pf - pi / t ∝ F
Momentum ( P) = mv .
mv - mu / t ∝ F
F ∝ m ( v-u) /t
F ∝ ma.
F = kma.
hope there is no mistake
(⌒o⌒)
m= mass of the body
u= initial velocity of the body
v= final velocity of the body
t= time for which the force is applied
F = an external force applied on body
pf - pi / t ∝ F
Momentum ( P) = mv .
mv - mu / t ∝ F
F ∝ m ( v-u) /t
F ∝ ma.
F = kma.
hope there is no mistake
(⌒o⌒)
Answered by
14
Newton's second law of motion :
It states that rate of change of linear momentum is directly proportional to the external force applied on the body .
F ∞ p/t
Initial velocity = u
Final Velocity = v
Change in momentum = mv-mu
F ∞ m(v-u/t)
As , a = v-u/t
F ∞ ma
Kg m /sec² = Newton
gm cm/sec² = Dyne
F = ma
1 N = kg m sec²
1 N= Force is said to be 1 N if it produces an acceleration of 1 m/sec² in a body of mass 1 kg .
#Be Brainly !!
It states that rate of change of linear momentum is directly proportional to the external force applied on the body .
F ∞ p/t
Initial velocity = u
Final Velocity = v
Change in momentum = mv-mu
F ∞ m(v-u/t)
As , a = v-u/t
F ∞ ma
Kg m /sec² = Newton
gm cm/sec² = Dyne
F = ma
1 N = kg m sec²
1 N= Force is said to be 1 N if it produces an acceleration of 1 m/sec² in a body of mass 1 kg .
#Be Brainly !!
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