Question

State Newton’s Third kinematical equation of motion.

Answer 1

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Answer:

In circumstances of constant acceleration, these simpler equations of motion are usually referred to as the SUVAT equations, arising from the definitions of kinematic quantities: displacement (s), initial velocity (u), final velocity (v), acceleration (a), and time (t).

Third Equation of Motion

• If body starts from rest, its Initial velocity = u = 0.
• If we drop a body from some height, its Initial velocity = u = 0.
• If body stops, its Final velocity = v = 0.
• If body moves with uniform velocity, its Acceleration = a = 0.

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Gm❤

Answer 2

Third Equation of Motion

it is denoted by

v2-u2 = 2as

Where

v = Final Velocity

u = Initial Velocity

S = Distance Travelled

a = acceleration

Third Equation of Motion - Derivation

22-u= 2as

Derivation We know that ,

$displacement = \frac{initial \: velocity \: + final \: velocity}{2} \times time$

$s = ( \frac{u + v}{2} ) \times t$

From First equation of motion,

v =u + at

v-u= at

$t = \frac{v -u}{a}$

Putting value of t in displacement formula

$s = ( \frac{v + u}{2} ) \times time$

$s = ( \frac{v + u}{2} ) \times ( \frac{v - u}{a} )$

$s = \frac{ {v }^{2} - {u}^{2} }{2a}$

$2as = {v}^{2} - {u}^{2}$

${v}^{2} - {u }^{2} = 2as$

To solve problems using equations of motion, we should remember that

• If body starts from rest, its Initial velocity = u = 0

If we drop a body from some height, its Initial

velocity = u = 0

If body stops, its Final

velocity = v = 0

• If body moves with uniform velocity, its

Acceleration = a = 0