Question

State newtons 2 law of motion .
A truck starts from rest and rolls down a hill with a constant acceleration. It travels a distance of 400 m in 20 s. Find its acceleration. Find the force acting on it if its mass is 7 tonnes

Answer 1

u = 0

s = 400 m

t = 20 second

m = 7 ✖ 1000 = 7,000 kg. (1 tonne = 1,000kg )

a =?

F=?

soo

s = ut +1/2 at square

put given numbers

400=0+1/2 a(20)square

=400/200

=2 m/s square

........now

F = m ✖ a

= 7,000 ✖ 2

= 14,000 N

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

u = 0 m/s

t = 20 s

s = 400 m

According to the second equation of motion:

s = ut + 1/2 at^2

400 = 0 + 1/2 × a × (20)^2

a = (400 × 2 )/400 = 2m/s^2

7 tons = 7000 kg

Now,

Force = mass × acceleration

⇒ F= 7000 × 2 = 14000 N

I hope, this will help you.

Thank you______❤

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