Physics, asked by jagdaleanuja9, 5 months ago

state of oscillation if phase angle is 1110°

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Answered by uttamrikibe3

Answer:

The time period of oscillation of a SHOSHO is π2sπ2s. Its acceleration at a phase angle π3radπ3rad from exterme position is 2ms−12ms-1. What is its velocity at a displacement equal to half of its amplitude form mean position? (in ms−1

Explanation:

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state of oscillation if phase angle is 1110°​

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state of oscillation if phase angle is 1110°