Math, asked by omchinchpure5, 5 days ago

state property of perpendicular bisector drawn from the centre of the circle on cord of a circle

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Answered by A1Equitas

5

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Answered by Nishu1215

2

Name center as A and the point where it the point on the cord as B and cord as EF

Step-by-step explanation:

It divide the EF into two equal halves
It nake right angle at EF
Every point in the perpendicular bisector is equidistant from point E and F

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