State pythagoras theorem class 10
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In a right angled square of hypothesis side =sum of its side and adjacent side
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.Pythagoras Theorem
Statement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
Given: A right triangle ABC right angled at B.
To prove: AC2 = AB2 + BC2
Construction: Draw BD perpendicular toAC
Proof :
We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.
triaADB and triABC
So, (Sides are proportional)
Or, AD.AC = AB2 ... (1)
Also, triBDCand triABC
So,
Or, CD. AC = BC2 ... (2)
Adding (1) and (2),
AD. AC + CD. AC = AB2 + BC2
AC (AD + CD) = AB2 + BC2
AC.AC = AB2 + BC2
AC2 = AB2 + BC2
Hope it help u
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Hence Proved.
Statement: In a right angled triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
Given: A right triangle ABC right angled at B.
To prove: AC2 = AB2 + BC2
Construction: Draw BD perpendicular toAC
Proof :
We know that: If a perpendicular is drawn from the vertex of the right angle of a right triangle to the hypotenuse, then triangles on both sides of the perpendicular are similar to the whole triangle and to each other.
triaADB and triABC
So, (Sides are proportional)
Or, AD.AC = AB2 ... (1)
Also, triBDCand triABC
So,
Or, CD. AC = BC2 ... (2)
Adding (1) and (2),
AD. AC + CD. AC = AB2 + BC2
AC (AD + CD) = AB2 + BC2
AC.AC = AB2 + BC2
AC2 = AB2 + BC2
Hope it help u
mark me as brainliest #AARUSHI
Hence Proved.
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