Question

state pythagoras therom​

Answer 1

(Hypotenuse)² = (Base)² + (Perpendicular)²

(H)² = (B)² + (P)²

Answer 2

$\huge\underline\bold \red {♡AnswEr♡}$

Statement: In a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

${\tt\red{Pythagoras \: theorem => h² = p² \: + b²}}$

Given: ABC is a triangle in which ∠ABC=90°

Construction: Draw BD⊥AC.

Proof:

In △ADB and △ABC

∠A=∠A [Common angle]

∠ADB=∠ABC [Each 90∘ ]

△ADB∼△ABC [A−A Criteria]

So,

AB / AD = AC / AB

Now, AB² =AD×AC ..........(1)

Similarly,

BC² =CD×AC ..........(2)

Adding equations (1) and (2) we get,

AB ²+BC²

=AD×AC+CD×AC

=AC(AD+CD)

=AC×AC

∴AB²+BC² =AC² [hence proved]

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