Question

state'pythagorus Theorem.

Answer 1

The Pythagoras theorem states that the square of the hypotenuse equals to the sum of the square of the perpendicular and the square of the base.

Answer 2

$<b><u><I>$☺✌ Hey there ! ☺✌

In a right triangle, the square of the hypotenuse is equal to the sum of the other two sides.

Give :- A right ∆ABC is right angled at B.

To Prove :- AC^2= AB^2+ BC^2

Proof :-

BD perpendicular on Ac

∆ ADB ~ ∆ ABC

AD/ AB = AB / AC •••••••••( sides are proportional)

AD•AC = AB^2 ••••••••( 1 )

∆ BDC ~ ∆ ABC

CD/ BC = BC/ AC

CD• AC = BC^2 •••••••••(2)

Adding eq (1) and (2)

AD• AC + CD• AC = AB^2 + BC^2

AC ( AD + CD ) = AB^2 + BC^2

AC• AC = AB^2 + BC^2

AC^2 = AB^2 + BC^2

Hence proved......

Hope it helps you ! ✌✌