Chemistry, asked by anshu2258, 4 months ago

State Raoult’s law for a solution containing non-volatile solute dissolved in volatile solvent.​

Answers

Answered by SWEETYASH
2

Raoult's law states that the relative lowering of vapour pressure of a solution containing a non- volatile solute is equal to the mole fraction of the solute in the solution.

Answered by ishuism000
9

Answer:

The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature multiplied by its mole fraction.

In equation form:

p

T

=p

B

0

B

In this equation, p

B

0

is the vapour pressure of the pure solvent at a particular temperature, p

T

is the total pressure of the solution, χ

B

is the mole fraction of the solvent.

For a solution of a volatile solute (A) and solvent (B) total pressure is sum of the partial pressure of the two as:

p

T

=p

A

0

A

+p

B

0

B

As χ

A

++χ

B

=1 or χ

A

=1−χ

B

or p

T

=p

A

0

.(1−χ

B

)+p

B

0

B

p

T

=p

A

0

+(p

B

0

−p

A

0

).χ

B

For non-volatile solute p

A

0

=0

thus p

T

=p

B

0

B

Limitations of Raoult's law:

1. Intermolecular forces between the solvent and solute components shoul be similar to those betweenindividual molecules

A_A=B-B=A-B

2. The gaseous phase are assumed to behave ideal where ideal gas law can be applied.

Similar questions