Question

state roults law for a sodium containing non voletile solute desolve in voletile solvent​

Answer 1

Answer:

The vapour pressure of a solution of a non-volatile solute is equal to the vapour pressure of the pure solvent at that temperature multiplied by its mole fraction.

In equation form:

pT=pB0.χB

In this equation, pB0 is the vapour pressure of the pure solvent at a particular temperature, pT is the total pressure of the solution, χB is the mole fraction of the solvent.

For a solution of a volatile solute (A) and solvent (B) total pressure is sum of the partial pressure of the two as:

pT=pA0.χA+pB0.χB

As χA++χB=1 or χA=1−χB

or pT=pA0.(1−χB)+pB0.χB

pT=pA0+(pB0−pA0).χB

For non-volatile solute pA0=0

thus pT=pB0.χB

Limitations of Raoult's law:

1. Intermolecular forces between the solvent and solute components shoul be similar to those betweenindividual molecules

A_A=B-B=A-B

2. The gaseous phase are assumed to behave ideal where ideal gas law can be applied.

Answer 2

Answer:

........

......

I think it's not