state that 3 root 7 is irrational.
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Let 3√7 is a rational number.
A rational number can be written in the form of p/q,
3√7 = p/q
√7 = p/3q
p,q are integers then p/3q is a rational number.
Then √7 is also a rational number.
But this contradicts the fact that √7 is an irrational number.
Therefore,our supposition is false.
So, 3√7 is an irrational number.
Hence proved.
Hope it helps...
A rational number can be written in the form of p/q,
3√7 = p/q
√7 = p/3q
p,q are integers then p/3q is a rational number.
Then √7 is also a rational number.
But this contradicts the fact that √7 is an irrational number.
Therefore,our supposition is false.
So, 3√7 is an irrational number.
Hence proved.
Hope it helps...
Denita1:
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