Question

state that the expression is a perfect square x^2 +8x +16​

Answer 1

$\bold \red{\underline{\underline{Answer:}}}$

$\bold\red{Yes \ it \ is \ a \ perfect \ square}$

${x^2 + 8x +16}$

${= x^2+4x+4x+16}$

${= x(x+4)+4(x+4)}$

${= (x+4)(x+4)}$

${= (x+4)^2}$

$\bold\green{Hence \ x^2+8x+16 \ is \ </p><p> a \ perfect \ square \ of \ (x+4)}$

Answer 2

Answer:

The given expression is a square of (x+4)

(x+4)^2

=x^2 + 2*x*4+4^2

=x^2+8x+16

hence proved