Question

state the atomicity of (1)phosphorus(2)Ca3(Po4)2(3)H2S2O7

Answer 1

Answer: atomicity of the following:

1. Phosphorus is 4.

2.Calcium phosphate is 13.

3. Disulfuric acid  is 11.

Explanation:

Atomicity is defined as total number of atoms present in the molecule.

Atomicity of phosphorous is 4.

$P_4=\text{total number of phosphorus atoms}=(4)=4$

Atomicity of calcium phosphate is 13.

$Ca_3(PO_4)_2=\text{total number of calcium atoms}+\text{total number phosphorus atoms}+\text{total number oxygen atoms}=(3)+(2)+(8)=13$

Atomicity of disulfuric acid  is 11.

$H_2S_2O_7=\text{total number of hydrogen atoms}+\text{total number of sulfur atoms}+\text{total number of oxygen atoms}=(2)+(2)+(7)=11$

Answer 2

Answer: 13 atoms

Explanation:

3 calcium, 2 phosphorus and 8 oxygen atoms. So, in total 13 atoms are present in this molecule.