state the change of g with the height about the earth's surface
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Therefore if a body is taken from pole to equator its distance from the centre of the earth will change. Consequently,the gravitational force also varies. ... Let g be the value of acceleration due to gravity at the surface of earth and g' at a height h above the surface of earth.
Since the radius of the Earth is 6378 km, that is our initial "r", if we are standing on the ground. That's our answer. At an altitude of 2642 km (approx. 1641 miles) above the Earth's surface, the gravitational acceleration will be 4.89m/s^2, which is half of 9.78 m/s^2 (the gravity at the surface).
Near the surface of the Earth (sea level), gravity decreases with height such that linear extrapolation would give zero gravity at a height of one half of the earth's radius - (9.8 m. s−2 per 3,200 km.)
Since the radius of the Earth is 6378 km, that is our initial "r", if we are standing on the ground. That's our answer. At an altitude of 2642 km (approx. 1641 miles) above the Earth's surface, the gravitational acceleration will be 4.89m/s^2, which is half of 9.78 m/s^2 (the gravity at the surface).
Near the surface of the Earth (sea level), gravity decreases with height such that linear extrapolation would give zero gravity at a height of one half of the earth's radius - (9.8 m. s−2 per 3,200 km.)
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