Question

State the chemical equation of


1) Oxidation
2) Reduction
​

Answer 1

Answer:

Here is the answer my friend

1) CuO(s)+H2(g)-------------->Cu(s) + H20(l) Oxidation H2 to H2O

2) 2Mg(s)+O2(g)------->2MgO(s). Reduction O2 to O

✅

Answer 2

Reduction: Fe3+(aq) + 3e– → Fe(s)

Oxidation: Mg(s) → Mg2+(aq) + 2e–