Physics, asked by anandmalgekar3068, 11 months ago

State the Coulomb’s law for the force acting between two definite point charges.

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Answered by aman7913
4

❇Coulomb's Law

Let’s say that there are two charges q1 and q2. The distance between the charges is ‘r’, and the force of attraction/repulsion between them is ‘F’. Then

F ∝ q1q2

Or, F ∝ 1/r2

F = k q1q2/ r2

where k is proportionality constant and equals to 1/4 π ε0. Here, ε0 is the epsilon naught and it signifies permittivity of a vacuum. The value of k comes 9 × 109 Nm2/ C2 when we take the S.I unit of value of ε0 is 8.854 × 10-12 C2 N-1 m-2.

According to this theory, like charges repel each other and unlike charges attract each other. This means charges of same sign will push each other with repulsive forces while charges with opposite signs will pull each other with attractive force.

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