Question

State the equation of the line which has the y-intercept equal to 4/3 and is perpendicular to
3x - 4y +11=0.​

Answer 1

Step-by-step explanation:

y/4/3 + x/a = I

y + 4x/3a = 4/3

y= -4X/3a + 4/3

y= mx +c

so on comparing we find, m(i)= -4/3a and c= 4/3.

now given that the line is perpendicular to

3x-4y+II=O

so 4y= 3x + II

y = 3x/4 + II/4

so here m(ii) = 3/4

now when two liner are perpendicular,

m(i)m(ii)= -I

then -4/3a× 3/4 = -I

solving it

we get a = I

now equation of line

y= -4X/3 + 4/3.

Answer 2

Answer:

4 x + 3 y - 4 = 0

Step-by-step explanation:

Given :

3 x - 4 y + 11 = 0

Write it in form y = m x + c

4 y = 3 x + 11

y = 3 / 4 x + 11 / 4

m₁ = 3 / 4

We know if line is perpendicular then their slope product is - 1.

m₁ m₂ = - 1

3 / 4 m₂ = - 1

m₂ = - 4 / 3

We have :

y-intercept c = 4 / 3

Now equation of line :

y = m₂ x + c

y = - 4 / 3 x + 4 / 3

3 y = - 4 x + 4

4 x + 3 y - 4 = 0

Therefore , equation of line is 4 x + 3 y - 4 = 0