Question

state the equation to find the relative density of a body with respect to a fluid if the weight of the body is known in air and in fluid​

Answer 1

Answer:

5.0±(1+10)%=5.0±11%

Explanation:

Weight in air = (5.00±0.05)N

Weight in water = (4.00±0.05)N

Loss of weight in water = (1.00±0.1)N

Now relative density =

weight-loss in water

weight in air

i.e., R.D=

1.00±0.1

5.00±0.05

Now relative density with maximum permissible error

1.00

5.00

±(

5.00

0.05

+

1.00

0.1

)×100

= 5.0±(1+10)%=5.0±11%

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