Question

state the following equation
have 2 distinct roots
(x-1)(x+2)+2=0 ​

Answer 1

Step-by-step explanation:

If we open the brackets in the equation (x - 1)(x + 2) + 2 = 0, we'll get:

x² + x - 2 + 2 = 0

x²+ x = 0

If we put in the value 0 we will get 0, in the right hand side. So 0 is a root of the equation.

Also, if we put in -1 we will get 0 on the right hand side. Therefore, -1 is also a root of this equation.

So, this equation has two distinct roots which are -1 and 0.

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