Question

State the formula for the end correction for a pipe closed at one end. If L1 & L2 are the resonating lengths for frequencies n1 &n2 respectively​

Answer 1

Explanation:

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Answer 2

Answer:

The frequency of the pth mode of vibration in an open organ pipe, 

ν=2(L+2e)pv

Where, e is the end correction of one side and L is the length of the pipe

Given : For  L=l1,     frequency of pth mode  =n1  

            For  L=l1,     frequency of pth mode  =n1 

 ⇒   n1=2(l1+2e)pv    .........(1)         

 ⇒n2=2(l2+2e)pv    ..........(2)

Dividiving (1) and (2), we get            

n2n1=2(l1+2e)pv×pv2(l2+2e)

∴    n2n1=l1+2el

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