State the Gauss's law in electrostatics using rhis law derive an expression for electric field due to charged thin spherical shell at a point outside the shell.
Answers
Explanation:
ANSWER
Gauss Law:
Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum.
Electric field due to a uniformly charged thin shell:
In the diagram, O is the centre of the spherical shell of radius R, and charge enclosed by the spherical shell is q.
Let a point A is outside the spherical shell, where we have to calculate the electric field.The distance between the centre of spherical shell and the point A.
ϕ=E.Scosθ
So, ϕ=E.4πr
2
−−−−−−−−−−−−−−(1)
As per gauss law,
ϕ=
ϵ
o
q
−−−−−−−−−(2)
From equation (1) and (2)
E.4πr
2
=
ϵ
o
q
Now,
E=
4πϵ
o
r
2
q
This is the electric field at the distance r, outside from the shell.
Gauss Law:
Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum.
Electric field due to a uniformly charged thin shell:
In the diagram, O is the centre of the spherical shell of radius R, and charge enclosed by the spherical shell is q.
Let a point A is outside the spherical shell, where we have to calculate the electric field.The distance between the centre of spherical shell and the point A.
ϕ=E.Scosθ
So, ϕ=E.4πr
2
−−−−−−−−−−−−−−(1)
As per gauss law,
ϕ=
ϵ
o
q
−−−−−−−−−(2)
From equation (1) and (2)
E.4πr
2
=
ϵ
o
q
Now,
E=
4πϵ
o
r
2
q
This is the electric field at the distance r, outside from the shell.
solution
Explanation:
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