Question

State the law of conservation of a momentum. A boy of 65kg mass is running with a velocity of 4m/s. He jump over a stationary cart of 3kg while running. find the velocity of cart after jumping of body.​

Answer 1

Answer:

Let v

1

and v

2

be the velocities of the boy and the trolley before the boy jumps in.

v

1

=2 and v

2

=0

The momentum p of the system boy-trolley before the jump,

p = Momentum of Boy + Momentum of trolley

p=35×2+70×0=70 Kg m/sec

Let V be the velocity of trolley ( with the boy in it ), the momentum of the trolley is

p=(35+70)V

By conservation of momentum, momenta are equal before and after interaction.

70=(35+70)V

V=0.7 m/sec to the right

Explanation:

hi bro/sis. this was ur answer. plz mark brainliest if u find it helpful