Question

state the law of conversation of linear momentum ball of mass 100f moving with velocity 10m/s stopped by boy in 0.2s calculate force to apply by ball boy to stop ball​

Answer 1

Answer:

mass of ball =100g , velocity of ball= 10m/s ,ball stop by boy in 0.2 sec.then force=mass×acceleration but acceleration is not given,acceleration=initial velocity - final velocity/time ,but initial velocity= 10m/s and final velocity=0m/s and time = 0.2 second. therefore,acceleration =10-0/0.2=50,therefore,force=m×a=100×50=500 Newton

Explanation:

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