Question

State the law of joule's law of heating 12 volt battery connected unknown resistor current of 2.5 in the circuit find the value of register of register

Answer 1

Answer:

We have potential difference (V) = 12V

Electric current (I)=2.5 mA= 2.4×10-3

According to Ohm’s Law (V) = IR

Or R = V/I

R=12v/2.4×10^-3

=12v×10^3/2.4

=120×10^3/24

=4.8×10^3

resistance is 4.8×10^3ohm

Answer 2

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—) 4.8×10^3ohm