Question

state the loading range available in the machine along with its least count ​

Answer 1

Explanation:

Solution:

Y=

lA

FL

since the experiment measures only change in the length of wire

∴

Y

ΔY

×100=

l

Δl

×100

From the obervation l

1

=MSR+20(LC) (MSR-Main Scale Reading)

l

2

=MSR+45(LC)

⇒ change in lengths = 25 (LC)

and the maximum permissible percentage error in elongation is one LC

∴

Y

ΔY

×100=

25(LC)

(LC)

×100=4