state the loading range available in the machine along with its least count
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Explanation:
Solution:
Y=
lA
FL
since the experiment measures only change in the length of wire
∴
Y
ΔY
×100=
l
Δl
×100
From the obervation l
1
=MSR+20(LC) (MSR-Main Scale Reading)
l
2
=MSR+45(LC)
⇒ change in lengths = 25 (LC)
and the maximum permissible percentage error in elongation is one LC
∴
Y
ΔY
×100=
25(LC)
(LC)
×100=4
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