Question

state the mean value theorem .verify it for the function f(x)=x and g(x)=sinx in the interval 0 to
$\pi$




​

Answer 1

Step-by-step explanation:

The function is differentiable not only in the open interval #(0, pi) but

also in the closed interval

[

0

,

π

]

. This is more than sufficient.

Here f '= cos x.

The MVT equation is

sin

π

=

sin

0

=

(

π

−

0

)

cos

c

→

cos

c

=

0

So,

c

∈

(

0

,

π

)

is

π

2

.