Question

state the nature roots for quadratic equation xsq+8x+8=0

Answer 1

Answer:

To determine the nature of roots of quadratic equations (in the form ax^2 + bx +c=0) , we need to caclulate the discriminant, which is b^2 - 4 a c. When discriminant is greater than zero, the roots are unequal and real. When discriminant is equal to zero, the roots are equal and real.

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#Hope it helps u

Answer 2

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

STEP

1

:

Equation at the end of step

1

:

(2x2 - 8x) + 8 = 0

STEP

2

:

STEP

3

:

Pulling out like terms :

3.1 Pull out like factors :

2x2 - 8x + 8 = 2 • (x2 - 4x + 4)

Trying to factor by splitting the middle term

3.2 Factoring x2 - 4x + 4

The first term is, x2 its coefficient is 1 .

The middle term is, -4x its coefficient is -4 .

The last term, "the constant", is +4

Step-1 : Multiply the coefficient of the first term by the constant 1 • 4 = 4

Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is -4 .

-4 + -1 = -5

-2 + -2 = -4 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2

x2 - 2x - 2x - 4

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-2)

Add up the last 2 terms, pulling out common factors :

2 • (x-2)

Step-5 : Add up the four terms of step 4 :

(x-2) • (x-2)

Which is the desired factorization