State the number of protons neutrons and electrons present in 47Ag108
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Explanation:
pandeji no idea about it i only read in class 8
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Answer:
A = 108; Z = 47
The number of protons (p) = 47
The number of electrons (e) = 47
The number of neutrons (n) = 61
Explanation:
This is predicted by these formulas.
Z=p=e
n=A-Z
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