State the output:
x + = y + 5 ; if x = 2 , y = 2
x= (a> b)? a : b ; if a = 2, b = 5
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5 == 5 True >>> 5 == 6 False ... n % 2 == 0 or n % 3 == 0 is true if either of the conditions is true, that is, if the number is divisible by 2 or 3. Finally, the not operator negates a boolean expression, so not(x > y) is true
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