State the Pauli's exclusion principle. Write the set of the four quantum numbers of the last three electrons of nitrogen atom.
Answers
Answer:
Pauli exclusion principle states that in a single atom no two electrons will have an identical set or the same quantum numbers (n, l, ml, and ms). To put it in simple terms, every electron should have or be in its own unique state (singlet state). ... Only two electrons can occupy the same orbital.
The last electron added is a 3p electron. Therefore, n = 3 and, for a p-type orbital, l = 1. The ml value could be –1, 0, or +1.
Answer:
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Explanation:
The Pauli Exclusion Principle states that, in an atom or molecule, no two electrons can have the same four electronic quantum numbers. As an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins. This means if one is assigned an up-spin ( +1/2), the other must be down-spin (-1/2).
Electrons in the same orbital have the same first three quantum numbers, e.g., n=1 , l=0 , ml=0 for the 1s subshell. Only two electrons can have these numbers, so that their spin moments must be either ms=−1/2 or ms=+1/2 . If the 1s orbital contains only one electron, we have one ms value and the electron configuration is written as 1s1 (corresponding to hydrogen). If it is fully occupied, we have two ms values, and the electron configuration is 1s2 (corresponding to helium). Visually these two cases can be represented as
pauli-exclusion-principle.jpg
As you can see, the 1s and 2s subshells for beryllium atoms can hold only two electrons and when filled, the electrons must have opposite spins. Otherwise they will have teh same four quantum numbers, in violation of the Pauli Exclusion Principle